Question

Li is going to paint a door that measures 195 cm by 74 cm.
He is going to give it two layers of paint on each side.
One tin of paint covers 5 m .
How many tins of paint does Li need to buy? ?
Show how to check your answer.

Answer 1

$\bigstar\:\:\underline{\sf AnsWer :} \: \bigstar$

The length of door is = 197 cm

And the breath of door is = 74 cm

Now first find its area =

Area= L× B

So 197× 74 = 14578 cm

Now let change the area in m by cm

1 m=100cm

So devide 14578 by 100 to change cm in meter

So we get = 145.78 m*2

Now if one tin covers 5m*2 then devide 145.78 m *2 by 5m*2

29.156 tins ...for one layer

So multiply 28.156 tins×2

58.312 tins are needed for the duble layer of paint of door

Answer 2

$\huge \pink{answeR}$

The length of door is = 197 cm

And the breath of door is = 74 cm

Now first find its area =

Area= L× B

So 197× 74 = 14578 cm

Now let change the area in m by cm

1 m=100cm

So devide 14578 by 100 to change cm in meter

So we get = 145.78 m*2

Now if one tin covers 5m*2 then devide 145.78 m *2 by 5m*2

29.156 tins ...for one layer

So multiply 28.156 tins×2

58.312 tins are needed for the duble layer of paint of door