Question

LIC
If the zeroes of polynomial x³-3x²+x+1
are a-b, a , at , then find the value
of a and b
​

Answer 1

Step-by-step explanation:

Given:-

→ p(x)= x³ -3x² +x+1

and the zeroes are

→ (a-b), a ,(a+b)

Here ,

→ a = 1

→ b = -3

→ c = 1

→ d = 1

→ a - b + a + a + b = -(-3)/1

→ 3a = 3

→ a = 3/3

→ a = 1.

Now,

→ (a - b) (a) (a+b) = -d/a

→ (a-b) (a+b) (a)= -1/1

→ a² - b² × a = -1

put the value of a in it,

→ 1² - b² ×1 = -1

→ 1 - b² = -1

→ -b² = -1-1

→ -b² = -2

→ b = ±√2

hope it helps you