Question

lif the distance between the points (4,k) and (1,0)is 5,then what can be the possible values of k​

Answer 1

Answer:

√(4-1)^2+(k-0)^2=5

9+k^2=25

k^2=16

k=4,-4

Answer 2

Answer:

let the point X(4, k) and You(1, 0)

It is given that the distance XY is 5 units.

By using distance formula

XY=√(4-1)^2+k^2

5 =√ 9-k

square both sides

25 =9+k^2

k^2= 16

k=4