Question

lift is moving downwards with an acceleration of 1.8 m/s. what is the apparent weight realised by a man of mass 50 kg.​

Answer 1

The apparent weight released by the man is 400 N.

Explanation:

Acceleration of the lift, $a=1.8\ m/s^2$

Mass of the man, m = 50 kg

We need to find the apparent weight released by a man when the lift us moving down wards. The apparent weight is given by :

W = m(g-a)

g is the acceleration due to gravity

$W=50\times (9.8-1.8)$

W = 400 N

So, the apparent weight released by the man is 400 N. Hence, this is the required solution.

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Lift is moving downwards with an acceleration of 1.8 m/s. what is the apparent weight released by a man of mass 50 kg. ?

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Answer 2

Answer:

acceleration 1.8ms‐¹

mass 50 kg

R=m(g-a),R<W

Explanation:

=50×(9.8×1.8)

=50×(8.0)

=400N

R=400N

Apparent weight is lesser than the actual weight.