Question

Light falling on metallic surface of work function 2ev is given by b=100[sin(5Ã10^15)t +cos(8Ã10^15)t]. Then maximum kinetic energy of the photoelectrons is______ 2 years ago

Answer 1

Then maximum kinetic energy of the photoelectrons is 3.25 eV

Explanation:

As we know that the wave equation of light is given as

$B = 100(sin(5\times 10^{15}t) + cos(8\times 10^{15}t))$

so the maximum possible frequency of the light is given as

$f = \frac{8\times 10^15}{2\pi}$

now the incident maximum energy of the light is given as

$E = hf$

$E = (6.6 \times 10^{-34})(\frac{8\times 10^15}{2\pi})$

$E = 8.4 \times 10^{-19} J$

as we know that

$1eV = 1.6 \times 10^{-19} J$

so we will have

$E = 5.25 eV$

now by Einstein's Equation of energy

$E = h\nu + KE$

$5.25 = 2 + KE$

$KE = 3.25 eV$

#Learn

Topic : Photoelectric effect

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Answer 2

Answer:3.25 eV

Explanation: