Light falls on the surface AB of a rectangular slab from air. Determine the smallest refractive index n that the material of the slab can have so that all incident light emerges from the opposite face CD
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angle of incident= i
angle of reflection= r
refractive index= n
Sin i = n Sin rIf the ray is to be reflected from the surface perpendicular to AB
Sin (90 – r) = Cos r >= 1/n (1)(1 – S2irn)1/2 >= 1/n1 + S2i n< =2n
The largest value of Sin2i = 1Hence n 2 >= 2n = 2½
angle of reflection= r
refractive index= n
Sin i = n Sin rIf the ray is to be reflected from the surface perpendicular to AB
Sin (90 – r) = Cos r >= 1/n (1)(1 – S2irn)1/2 >= 1/n1 + S2i n< =2n
The largest value of Sin2i = 1Hence n 2 >= 2n = 2½
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