Question

Light is incident on a clear plasti block at an angle of 45° . the speed of light in the plastic is c/√2, where c is the speed of light in vacuum . find the angle of refraction

Answer 1

Given,

$i = 45 \textdegree \\ \\ \text{ let the spped of light in vaccum be} \ v_1 \ \text{and speed of light in block be } \ v_2 \\ \\ v_1 = c \\ \\ v_2 = \frac{c}{\sqrt{2}} \\ \\ \textbf{We know that, According to Snell's law} \\ \\ \frac{\sin i}{\sin r} = \frac{v_1}{v_2} \\ \\ \frac{\sin 45\textdegree}{\sin r} = \frac{c}{\frac{c}{\sqrt{2}}} \\ \\ \frac{\sin 45\textdegree}{\sin r} = \sqrt{2} \\ \\ \frac{\frac{1}{\sqrt{2}}}{\sin r} = \sqrt{2} \\ \\ \sin r = \frac{1}{2} \\ \\ \sin r = \sin 30\textdegree \\ \\ r = 30$

r = 30°

Answer 2

Answer:

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