Question

Light is incident on an air-water interface at an angle of 25° to the normal. What angle does the refracted
ray make with the normal ?
(a) 19° (b) 34° (c) 25° (d) 90°

Answer 1

Here according to the question

light is travelling from a medium of higher density to a medium of lower density,then n2(for air) > n1( for water),and the angle of refraction (θ1 ) is larger than the angle of incidence (θ2) .thus the light bends away because the lights go to the air from water.

From Snell's law ,n1 sinθ1 = n2 sin θ2

according to the question θ2 = 25°

and for air n1 = 1.00003 ,for water n2= 1.3330

according to the Snell's law

sinθ1/sinθ2= n2/n1

or sin θ1= (1.333÷1.00003)× sin 25°

or θ1= 34°

so the answer would be (b) 34°

Answer 2

Answer:

19*

Explanation:

option a