Question

light of wavelength 310 nanometres falls on the surface having workfunction 2 e.v • calculate 1•Energy of incident light,2• frequency of incident light,3• threshold frequency,4• kinetic energy of ejected electron, 5• velocity of ejected electron,6• stopping potential
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Answer 1

Answer:

Energy of incident radiation is given by:

E=

λ

hc

=

300∗10

−9

6.64∗10

−34

∗3∗10

8

=6.64∗10

−19

=4.05eV

The work function of the metal is equal to 2.54eV

Hence the maximum kinetic energy of an ejected photoelectron would be 1.59eV

And the stopping potential needed to stop this would be 1.59V.

Explanation:

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