Question

Light of wavelength 4000 A0 falls on the surface of cesium. Calculate the energy of the photoelectron emitted. The critical wavelength for photoelectric effect in cesium is 6000A0.

Answer 1

Answer:

Explanation:

Light of wavelength 4000 A0 falls on the surface of cesium. Calculate the energy of the photoelectron emitted. The critical wavelength for photoelectric effect in cesium is 6000A0.

Light of wavelength is 4000 angstrom

By using the formula Hf = K + W

K = hf - W

K = hc * (1/λ - 1/λo)

K = 12400 eV Å * (1/ (4000 Å) - 1/ (6000 Å) )

K = 1.33ev

Therefore, answer: - Kinetic energy of photoelectrons emitted i 1.33ev