Light of wavelength 4000 Angstrom falls on the surface of a Cesium calculate the energy of photoelectrons emited the critical wavelength for photoelectric effect in Cesium is 6600 Angstrom
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Light of wavelength 4000 Angstrom falls on the surface of cesium |Calculate the energy of the photoelectronemitted if the critical wavelength for photoelectric
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E = 1.957*10^-19 J
Explanation:
E = hv - hv0
= h(v - v0) = hc(1/λ - 1/λ0)
where, hv0 = work function of metal
E = 6.626*10^-34*3*10^8(1/4000*10^-10 - 1/6600*10^-10)
= 19.878*10^-26(2600*10^-10/264*10^-18)
= 195.768*10^-21
= 1.957*10^-19
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