Physics, asked by sharmakanak945087, 7 months ago

light of wavelength 4400 Angstrom a metallic surface whose work function is 2.5 ev.calculate maximum K.Eof emitted electron.

Answers

Answered by chaithanya305

1

Answer:

hV=hVo+K.Emax

work function =2.5

λ=4400

hc/λ=hc/λo+K.Emax

12400/λ=2.5+K.Emax

12400/4400 -2.5=K.Emax

2.81-2.5=K.Emax

K.Emax=0.31 j

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