Physics, asked by Klklkl2216, 11 months ago

Light of wavelength 500 nm is incident on a metal with work
function 2.28 eV. The de Broglie wavelength of the emitted
electron is: [2015 RS]
(a) < 2.8 × 10⁻⁹ m (b) ³. 2.8 × 10⁻⁹ m
(c) £ 2.8 × 10⁻¹² m (d) < 2.8 × 10⁻¹⁰ m

Answers

Answered by mehlikeme
0

a.6287

b.2844

c.2859^90

d..2849^28

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