Light of wavelength 500 nm is incident on a slit of width 0.1 mm. The width of the central bright line on the screen is 2m. What is the distance of the screen?
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Given : wavelength of light, λ = 500 nm
width of slit, d = 0.1 mm
width of central bright line on the screen, y = 2m
To find : the distance of the screen from the slit.
solution : using formula, width of central Maxima, y = 2λD/d
⇒D = yd/2λ
= (2 m × 0.1 mm)/(2 × 500 nm)
= (2 × 10¯⁴)/(10¯⁶)
= 200 m
Therefore the distance of the screen is 200m from the slit.
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