Physics, asked by swami2999, 10 months ago

Light of wavelength 5000 Å propagating in air gets partly reflected from the surface of water. How will the wavelengths and frequencies of the reflected and refracted light be affected?

Answers

Answered by facttenz
3

wavelength is = 5000

frequency of reflected and refracted light is going to be the same .

therefore,

frequency,v=c/wavelength

=3×10 to the 8/5000×10 to the power minus10

frequency = 6×10 to the power 14hz

Answered by Anonymous
30

\Large{\red{\underline{\underline{\sf{\pink{Solution:}}}}}}

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\hookrightarrow Wavelength of incident light, \sf \lambda\:=\:5000\,Å\:=\:5000\times 10^{-10}m

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\hookrightarrow Speed of light, \sf c\:=\:3\times 10^8ms^{-1}

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Frequency of the incident light is given by the relation,

\sf v\:=\: \dfrac{c}{\lambda}

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\sf v\:=\: \dfrac{3\times 10^8}{5000\times 10^{-10}}

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\sf \longrightarrow\,v\:=\:6\times 10^{14}Hz

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\hookrightarrow The wavelength and frequency of incident light is the same as that of reflected ray. Hence, the wavelength of reflected light is \sf{\red{5000\,Å}} and its frequency is \sf{\red{6\times 10^{14}Hz}}

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