Question

Light of wavelength 560 nm goes through a pinhole of diameter 0.20 mm and falls on a wall at a distance of 2.00 m. What will be the radius of the central bright spot formed on the wall?

Answer 1

Given:

Wavelength of the light used λ=560 nm=560×10⁻⁹ m

Diameter of the pinhole, d = 0.20 mm = 2 × 10⁻⁴ m

Distance of the wall, D = 2m

We know that the radius of the central bright spot is given by

R=1.22λD/d   =1.22×560×10⁻⁹×2/2×10⁻⁴  

=6.832×10⁻³ m

or=0.683 cm

Hence, the diameter 2R of the central bright spot on the wall is 1.37 cm.

Answer 2

Answer:

Answer. Hence, the diameter 2R of the central bright spot on the wall is 1.37