Question

Light of wavelength 589.3 nm is incident normally on
two slits of separation 0.1 nm width 0.01 nm. The
angular width of the central diffraction maximum at a
distance of 1 m from the slits is​

Answer 1

Answer:

Let D be the distance between source and screed d the distance between coherent source then for central diffraction maxima,

where λ is wavelength

Given, λ=589.3nm=589.3×10

−9

m

d=0.1×10

−3

m,D=1m

∴W=

0.1×10

−3

2×589.3×10

−9

×1

Angular width

θ=

D

W

=

0.1×10

−3

2×589.3×10

−9

rad=0.68

∘

MArk me as a brain list

And follow me