Physics, asked by gaurav6706, 1 year ago

Light of wavelength 6.5 × 10⁻⁷ m is made incident on two slits 1 mm apart. The distance between third dark fringe and fifth bright fringe on a screen distant 1 m from the slits will be(a) 0.325 mm(b) 0.65 mm(c) 1.625 mm(d) 3.25 mm

Answers

Answered by MoonGurl01
2

Hey!! ☺

Here is your answer

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0.06 cm. and first bright fringe. distance between two slits is 0.05 cm and the distance of screen from the slits is 1 m. In Young's double slit experiment the slits are 5 mm apart and interference is.The intenererice mng the third dark fringe and the fifth bright fringe.

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Thanks!! ✌

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