Light of wavelength 600 nm falls on glass plate at angle of incidence calculate smallest thickness
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Answer:
Given:
λ=5.88×10−7m
μ=1.5
r=600
To find :
t
Solution :
For Destructive interference on a reflected side of thin film:-
2μcosr=nλ
(For minimum thickness, n=1)
2(1.5)tcos(60)=5.88×10−7
t=3.92×10−7
t=0.392μm
hope this might help you
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