Question

Light of Wavelength 6000
angstrom falls normally on a
thin wedgeshaped film of
refractive index 1.35 forming
fringes that are 2mm apart. find
the angle of wedge film​

Answer 1

Answer:

NCERT me hai iska answer ...

Answer 2

Given,

          Light of wavelength (λ) = 6000Α°

           Refractive index (μ)      = 1.35

           Fringe width (B)            = 2mm

To Find: The angle of wedge film?

Explanation:

as the fringe width is given by,

                                    B = (λ) / $2$θμ    ⇒equation(1)

as we can find the angle of wedge then by equation(1),

                                    θ = (λ) / $2$μB

                   (where, θ is angle of wedge)

on putting values into the formula,

                                    θ = ($6000$×$10^{-10}$) ÷ [$2$×$1.35$×($2$×$10^{-3}$)]

                                    θ = $1.11$×$10^{-4}$    

Hence the angle of wedge is 1.11×$10^{-4}$