Question

Light of wavelength $6328 \AA$ is incident normally on a slit having a width of 0.2 mm. The angular width of the central maximum measured from minimum to minimum of diffraction pattern on a screen 9.0 metres away will be about
(a) 0.36 degree
(b) 0.18 degree
(c) 0.72 degree
(d) 0.09 degree

Answer 1

For this question option B

Answer 2

Answer:

answer is option a 0.36 degree

Explanation:

angular width of central bright fringe is 2lambda/d=2×6328×10^-10/0.2×10^-3 ×180/π = 0.36 degree

Hence option a is correct