Question

Light rays travel from vacuum into a glass, whose angle incidence is 45°, and angle of refraction is 30°. Calculate the refractive index of the glass​

Answer 1

Answer:

$\boxed{\mathfrak{Refractive \ index \ of \ glass \ (\mu_g) = \sqrt{2}}}$

Explanation:

Refractive index of vacuum ($\sf \mu_v$) = 1

Angle of incidence (i) = 45°

Angle of refraction (r) = 30°

From Snell's Law:

$\boxed{ \bold{\mu_v \: sin \: i = \mu_g \: sin \: r}}$

$\rm \mu_g \longrightarrow$ Refractive index of glass

By substituting value in the equation we get:

$\rm \implies 1 \: sin \: 45 \degree = \mu_g \: sin \: 30 \degree \\ \\ \rm \implies \dfrac{1}{ \sqrt{2} } = \mu_g \times \dfrac{1}{2} \\ \\ \rm \implies \mu_g = \dfrac{2}{ \sqrt{2} } \\ \\ \rm \implies \mu_g = \sqrt{2}$

Answer 2

Answer:  Answer:Since it's vacuum, refractive index is taken to be 1. use snell's law of refraction n1xsin(i)=n2xsin(r) n1=1 sin(i)=sin(2r) n2=1.5 sin(r)=sin(r) ... has maximum angle of refraction when travelling from glass to air for same angle of incidence? .If a ray of light travelling through the air strikes a glass slab at an angle of 30°.