light source of wavelength illuminates metal & eject photo elect vous a Maximum koe OF 1.00 ev. A second light source with half the wavelength of the first the first ejects photo electrons Maximum K.E work function of the metal? 4.00 ev with a a OF Determine work function of the metal
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Answer:
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Explanation:
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Answer:
E=KE+W
E is the total energy of the incident light source (E=hν=
λ
hc
)
KE is the kinetic energy of the ejected photoelectron
W is the work function of the metal. It is constant for a particular metal.
When light of wavelength λ is incident on a metal then,
λ
hc
=1+W
When light of wavelength
3
λ
is incident
λ/3
hc
=5+W
λ
3hc
=5+W
Putting the value of
λ
hc
, we get
3(1+W)=5+W
2W=2
W=1eV
Explanation:
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