Light takes t₁ sec to travel a distance x in vacuum and the
same light takes t₂ sec to travel 10 cm in a medium. Critical
angle for corresponding medium will be
(a) sin⁻¹ (10 t₂/t₁X) (b) sin⁻¹ (t₂ X/10 t₁)
(c) sin⁻¹ (10 t₁/t₂ X)(d) sin⁻¹ (t₁X/10 t₂)
Answers
Answered by
2
v = 10/t2
sin i = 1/n = v/c
c = x /t1
sin i = 10/t2 x t1/x
= 10t1/ t2x
sin⁻¹ (10 t₁/t₂ X)
Answered by
2
Answer:
Option (C) is the correct answer.
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