Question

Light traveling through an optical fiber(n=1.44) reaches the end of the fiber and exists into air . If the angle of incidence on the end of the fiber is 30 degres. What is angle of refraction outside the fiber

Answer 1

as refractive index =

$\frac{angle \: of \: incidence}{angle \: of \: refraction} = \frac{x}{y}$

so... putting values.

$1.44 = \frac{30}{y}$

we get y = angle of refraction

= 20.8 degrees

hope it helps

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