Question

Light Travels from a rarer medium 1 to denser medium 2. Angle of incidence = 45° and. Angel of refraction is 30°. Calculate the refractive index of 2nd medium with respect to the first.


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Answer 1

Heya mate !!!!!

Here's your answer =>=>

As we are given ===

Angle of incidence = 45°

and

Angle of refraction = 30°

According to the laws of refraction = angle of incidence / angle of refraction

$\frac{ \sqrt{45} }{ \sqrt{30} } \\ = \frac{ \frac{1}{ \sqrt{2} } }{ \frac{1}{2} } \\ = \frac{1}{ \sqrt{2} } \times \frac{2}{1} \\ = \frac{2}{ \sqrt{2} } \\ = 1.414$

Hope it will help you ☆▪☆

Thanks ^_^

@Beautiful5225

Answer 2

Answer:

The refractive index if 2nd medium with respect to 1st medium is

$\sqrt{2}$

Explanation:

Given that,

A light travels from a rarer medium to denser medium.Also given that,

Angle of incidence(i)=45°

Angle of refraction(r)=30°

According to Snell's Law we have a relation between refractive indexes of two media and the angles as

$µ _{1}sin(i) = µ _{2}sin(r)$

The refractive index of 2nd medium with respect to 1st medium is

$µ _{21} = \frac{µ _{2}}{µ _{1}} \\ = \frac{sin \: i}{sin \: r} \\ = \frac{sin45}{sin30} = \frac{ \frac{1}{ \sqrt{2} } }{ \frac{1}{2} } = \frac{2}{ \sqrt{2} } = \sqrt{2}$

Therefore,the refractive index of 2nd medium with respect to 1st medium is is

$\sqrt{2}$

#SPJ2