light wavelength lamda1 enters a medium with refractive index n2from a medium with the refracive index n1 what is the wavelenght of the light in second medium
Answers
Snell's law of refraction is n(1) sinθ(1) = n(2) sinθ(2), where θ(1) and θ(2) are the angles of incidence (off of the normal or perpendicular) and refraction, respectively, of a ray crossing the interface between two media with refractive indices n(1) and n(2). The index of refraction in a vacuum is exactly 1. So from this, you can figure out the refractive incidence of medium 1 with respect to medium 2. What this really comes from is the speed of light in various mediums. Again I cite the excerpt from the Wikipedia article "Index of Refraction": The speed of light in a medium is v = c/n, and similarly the wavelength in that medium is λ = λ(0)/n, where λ(0) is the wavelength of that light in vacuum. A vacuum has a refractive index of 1; the frequency (f = v/λ) of the wave is not affected by the refractive index. Only the wavelength and velocity of the wavefront change in different media.
Explanation:
πr²
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