Question

Light waves from two current source having intensities I and 4i cross each other at a point with the phase difference of 90 degree what is the resultant intensity at the point

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

5I

Explanation:

The resultant intensity at a point where phase difference is Φ is

IR +I1 + I2 2  +I1I2−−−−√I1I2 cos Φ

As I1 + I and I2 = 4I, therefore,

 IR = I + 4I + 2 I.4I−−−−√I.4I cos Φ  

IR = 5I + 4I cos Φ

(i) When Φ = 0 ; IR = 5I + 4I cos 0 = 9I  

(ii) When Φ =π2π2 ; IR = 5I + 4I cos π2π2 = 5I

 (iii) When Φ = π ; IR = 5I + 4I cos π = 51 – 41 = I

Φ = 0 ; IR = 9I

Φ = π2π2  IR = 5I

Φ = π  IR=I