Physics, asked by sauravkumar4121, 8 months ago

Light waves producing interference have their amplitudes in the ratio 3:2. The intensity ratio of maximum and minimum interference fringes is

Answers

Answered by drjiya123

1

Amplitudes ratio is 3/2

Let amplitudes by 3x and 2x

At maxima amplitudes add up giving 5x

At minima amplitudes substract giving −x

Intensity ratio =25/1

because Intensity is square of amplitude.

Answered by Anonymous

0

Answer:

Amplitudes ratio is 3/2

Let amplitudes by 3x and 2x

At maxima amplitudes add up giving 5x

At minima amplitudes substract giving −x

Intensity ratio =

1

25

because Intensity is square of amplitude.

Explanation:

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