Light with an energy flux of 25 × 10⁴ Wm⁻² falls on a perfectly reflecting surface at normal incidence. If the surface area is 15 cm², the average force exerted on the surface is:(a) 1.25 × 10⁻⁶ N(b) 2.50 × 10⁻⁶ N(c) 1.20 × 10⁻⁶ N(d) 3.0 × 10⁻⁶ N
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For this question option D
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Answer:
B) 2.50 x 10⁻⁶ N.
Explanation:
Energy flux = 25 × 10⁴ Wm⁻²
Surface area = 15 cm²
Average force = Δp\Δt
Light falls on a perfectly reflecting surface at normal incidence.
Since the surface is perfectly reflecting, thus - Δp = 2Δt/c
F = 2 × [ΔE/cΔt]
F = 2 ×p/c
F = 2 x (25 x 10 x 15 x 10) / ( 3 x 10⁸)
F = 2.5 x 10⁻⁶ N
Therefore, the average force exerted on the surface is 2.50 x 10⁻⁶ N.
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