Light with an energy flux of 25 x 10^4 W m^-2 falls on a perfectly reflecting surface at normal incidence.
Answers
Answered by
49
REFER TO THE ATTACHMENT
Attachments:
Answered by
18
Answer :- 2.5 x 10⁻⁶ N.
=> It is given that,
energy flux = 25 x 10⁴ wm⁻²
Surface area = 15 cm²
=> For the Average force extend on the surface = Δp /Δt
=> Here, Light falls on a perfectly reflecting surface at normal incidence.
∴ Δp = 2Δt/c
F = 2*[ΔE/cΔt]
= 2*p/c
= 2 x (25 x 10 x 15 x 10) / ( 3 x 10⁸)
= 2.5 x 10⁻⁶ N
Therefore, the average force exerted on the surface is 2.5 x 10⁻⁶ N.
Similar questions