Math, asked by mamukherjee, 6 months ago

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Answered by rimpy754
11

Answer:

given:

the top of a rectangular box of sides 50 cm by 30 is covered with a tape of breath 17 cm .

to find:

what is the length of tape?

solution

length be x

p = 2(l \times b) \\ 2(50 + 30) = 2(x + 17) \\ 100 + 60 = 2x + 34 \\ 160 = 2x + 34 \\ 160  - 34 = 2x \\ 126 = 2x \\ x   \frac{126}{2}  \\ x = 63

this is your answer

Answered by pravinrin
1

Answer:

The length of the tape used is 90 CM

Step-by-step explanation:

Given: Top of the rectangular box is covered with a tape

Area of the top of the rectangular box is = 50 x 30 = 1500 Sq.CM

Area of the tape= 17 x L=17L

Length of the tape = 1500/ 17 = 88.23 CM.

However, this is not practical because we need to cut the tape into many pieces to achieve this.

We will see the other options:

1. Let's stick the tape along the length:

30/17= 1.764. Therefore,  we need two strips.

Length of the tape = 2 x 50 (two strips x length) = 100 CM

2. Let's stick the tape along the width

50/17= 2.94. Therefore, we need three strips

Length of the tape = 3 x 30 (three strips x width) = 90CM

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