Like find the three consecutive numbers who sum is 63
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For easiest solution, Let three consecutive numbers be (x-1), (x), (x+1),
Now according to the question, Their sum = 63,
=> (x-1) + (x) + (x+1) = 63,
=> 3x = 63,
=> x = 21,
We got the middle number of three numbers,
Now previous number = x-1 = 20,
Now next number = x+1 = 22,
So the numbers are 20, 21, 22,
Hope you understand, Have a great day !!
Now according to the question, Their sum = 63,
=> (x-1) + (x) + (x+1) = 63,
=> 3x = 63,
=> x = 21,
We got the middle number of three numbers,
Now previous number = x-1 = 20,
Now next number = x+1 = 22,
So the numbers are 20, 21, 22,
Hope you understand, Have a great day !!
siddhartharao77:
I think their sum = 63
Answered by
2
Let the 3 consecutive integers be x, x+1, and x+2.
Given the sum of three consecutive numbers is 63.
x + x + 1 + x + 2 = 63
3x + 3 = 63
3x = 60
x = 20.
Substitute x = 20 into x + 1 and x + 2 to find the values ofsecond and third integer values.
x + 1 = 21 and x + 2 = 22.
The integers are 20,21 and 22.
Hope this helps!
Given the sum of three consecutive numbers is 63.
x + x + 1 + x + 2 = 63
3x + 3 = 63
3x = 60
x = 20.
Substitute x = 20 into x + 1 and x + 2 to find the values ofsecond and third integer values.
x + 1 = 21 and x + 2 = 22.
The integers are 20,21 and 22.
Hope this helps!
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