Math, asked by tubasadafzain, 28 days ago

Lilly's mother's age is eight times Lilly's age. After five years Lilly's mother will be five more than four times Lilly's age. What are their present ages? *

Answers

Answered by js6326742
22

Let's consider Lily's age as x

So Lily's mother's age would be 8x

Ater five years their ages will be (x+5) and (8x+5) respectively

According to question it is saying that after five years Lily's mother's age would be 5 years more than her daughter's age .

Inputting it into equation ;

{4(x+5)} +5 = 8x+5

4x + 20 +5 = 8x+5

4x+25 = 8x+5

Transposing similar terms on same sides :

4x-8x = 5-25

-4x = -20

Cancelling negative sign from both sides

4x=20

x = 20/4 =5

Their present ages are 'x' and '8x' respectively

::Inputting value of x

x= 5 years and 8x= 8×5 = 40 years

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