Question

lim θ→0 ​ θ 2 1−2cosθ+cos2θ ​÷ θ²​

Answer 1

Answer:

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Answer 2

Answer:

We know,

1 − cos^2^θ = sin^2^θ.

⇒limθ → 0.

sin^2θ^θ^2

⇒limθ → 0.

(sinθ^θ)2

Use an approximation for, sinθ,

⇒sinθ = θ − θ^3^3!.

⇒limθ → 0.

⎛⎝θ − θ^3^3!θ⎞⎠2

⇒limθ → 0.

(1 − θ^2^3!)^2 = 1.

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