lim
→0
log(1 − ) is equals to
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""" ❤️ Answer ❤️ """
limx→0[log(1+x)3x−1]
Dividing the numerator and the denominator by x:
limx→0[log(1+x)x⋅(3[∵limx→0log(1+x)x=1limx→
=1log3
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