lim 1-cos mx/ 1-cos nx ?
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Answered by
100
Things to know :
1) 1-cos a = 2 sin ^(a/2)
2) lim x ->0 sin x / x = 1 or sin^2(x)/x^2 = 1
Final Result : (m/n)^2
Steps involved :
1) Use eq: (1)
2) Multiply and divide by (m/2)^2 and (n/2)^2.
3) Use eq. (2)
Hope, you understand my answer.
1) 1-cos a = 2 sin ^(a/2)
2) lim x ->0 sin x / x = 1 or sin^2(x)/x^2 = 1
Final Result : (m/n)^2
Steps involved :
1) Use eq: (1)
2) Multiply and divide by (m/2)^2 and (n/2)^2.
3) Use eq. (2)
Hope, you understand my answer.
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Answered by
22
Answer:
plz check above....
Step-by-step explanation:
answer is m^2/n^2
Attachments:
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