lim 3-√5+x/1-√5-x
x tend to 4
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Answer:
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Step-by-step explanation:
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Answered by
0
Here, the limit has
0
0
form, so,
using dividendo and numendo rule,
i.e conjugates of denominator and numerator.
x→4
lim
(1−
5−x
)(3+
5+x
)(1+
5−x
)
(3−
5+x
)(3+
5+x
)(1+
5−x
)
x→4
lim
(1
2
−(5−x))(3+
5+x
)
(3
2
−(5+x))(1+
5−x
)
x→4
lim
(x−4)(3+
5+x
)
(4−x)(1+
5−x
)
x→4
lim
3+
5+x
−(1+
5−x
)
⇒
6
−2
=
3
−1
Attachments:
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