Question

Lim as x tends to 0 sinax /bx is

Answer 1

Answer:

$=>\frac{a}{b}$

Step-by-step explanation:

=> Were are given, $\lim_{x \to 0}\frac{sin(ax)}{bx}$

$=>\lim_{x \to 0}\frac{sin(ax)}{bx}=\lim_{x \to 0}\frac{sin(ax)}{ax}(\frac{ax}{bx})$

$=>\lim_{x \to 0}(\frac{sin(ax)}{ax})(\frac{a}{b})$

$=>\frac{a}{b}\lim_{ax \to 0}\frac{sin(ax)}{ax}$   [x-->0 => ax-->0]

$=> \frac{a}{b}(1)=\frac{a}{b}$    $[ \lim_{nx \to 0} \frac{sin(nx)}{nx} =1]$

Answer 2

Step-by-step explanation:

At x ·– 0, the value of the given function takes the from 0/0