Question

lim- f (x) - f(2) upon x-2 where f(x) = x²+x ​

Answer 1

Explanation:

Correct option is

B

−3(x−2)2

⇒f(x)+2f(1−x)=x2+2⋯⋯(i)

Put x=1−x

⇒f(1−x)+2f(x)=(1−x)2+2

Multiply by 2

⇒2f(1−x)+4f(x)=2(1−x)2+4⋯⋯(ii)

Subtract (ii) from (i)

−3f(x)=x2−2−2(1−x)2

−3f(x)=x2−2−2x2+4x

−3f(x)=−(x2−4x+4)

f(x)=−3(x−2)2