Math, asked by rachita07, 10 months ago

lim n-> infinity
$( {sin2x})^{n} is \: discontinuous \: at \: x =$

Answers

Answered by Anonymous

4

hey mate here is ur answer =

lim n-> infinty (sin2x)^n

using formula = e^limn->infinityn(x-1)

substitute in the formula

we get

e^(n(sin2x-1))

=now let x=pi/4

At x=+pi/4

e^(n(sin 90°-1))=e^0=1

At x=-pi/4

e^(n(sin(-90)-1))=e^-2=1/e^2

Lhs is not equal to rhs.

hence point is pi/4

hope it helps.

☆☆☆

Answered by Anonymous

0

Answer:

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