Question

Lim n tends to infinity (1+1/a1)(1+1/a2)(1+1/a3)... where a1=1 and an=n(1+an+1)

Answer 1

Answer:

7/2

Step-by-step explanation:

take a1=1, then a2=2&a3=3

then substitute the values

 [1+1/1][1+1/2]

=[1+1][1+1/2]

=2+3/2

=7/2