Question

lim n tends to infinity 1.2+2.3+3.4+...........+n(n+1) /n 3 (cube)​

Answer 1

Step-by-step explanation:

(n(n + 1))/n3

can be rewritten as (n2 + n)/n3.

Divide the numerator and denominator by n3:

(1/n + 1/n2)/1

For large values of n, the expression becomes:

(0 + 0)/1 or 0

Dividing 1 by large numbers yields small quotients whose values approach 0.

Answer 2

Step-by-step explanation:

this is answer.... as per steps