Question

lim
n tends to infinity
1/(2n-1)!
​

Answer 1

$\lim_{n \to \infty} \frac{1}{(2n-1)!}$ = 0

• A limit in mathematics is a point at which a function approaches the output for the specified input values. Calculus and mathematical analysis depend on limits, which are also used to determine integrals, derivatives, and continuity. It is employed in the analysis process and constantly considers how the function will behave at a specific point. The idea of the limit of a topological net broadens the definition of the limit of a sequence and relates it to the limit and direct limit in theory category.
• In general, there are two sorts of integrals: definite integrals and indefinite integrals. The upper limit and lower limit for definite integrals are correctly defined. As opposed to indefinite, which has an arbitrary constant while integrating the function, the integrals are expressed without any restrictions.

Here, according to the given information, we are given that,

$\lim_{n \to \infty} \frac{1}{(2n-1)!}$

Here, since n  tends to infinity, $\frac{1}{n}$ must tend to 0.

Hence, $\lim_{n \to \infty} \frac{1}{(2n-1)!}$ = 0.

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