Question

lim rightarrow 2 x²-4/ √x+2-√3x-2.
plz answer this question​

Answer 1

Answer:

$\frac{2x^2-4}{\sqrt{x}+2-\sqrt{3}x-2}=\frac{\left(2x^2-4\right)\left(\sqrt{3}x+\sqrt{x}\right)}{x-3x^2}$

Step-by-step explanation:

$\frac{2x^2-4}{\sqrt{x}+2-\sqrt{3}x-2}$

$=\frac{2x^2-4}{-\sqrt{3}x+\sqrt{x}}$

$=\frac{\left(2x^2-4\right)\left(\sqrt{3}x+\sqrt{x}\right)}{x-3x^2}$

HOPE IT HELPS

EVA*