Question

lim (sin4x+sin2x/6x)
x-
$>$




​

Answer 1

assuming lim is extending x->0

Answer:

1

Step-by-step explanation:

lim (sin4x/6x) + lim(sin2x/6x)

lim (4/4)*(6/6)*(sin4x/6x) + lim (2/2)*(6/6)*(sin2x/6x)

lim (4/6)*(sin4x/4x) + lim (2/6)*(sin2x/2x)

(4/6)*{lim (sin4x/4x)} + (2/6)*{lim (sin2x/2x)}

-----------------------------------------------------------[ lim sinx/x = 1]

(4/6)*1 + (2/6)*1

(4+2)/6

6/6

1