Question

lim [sin8x/tan4x]
x->0​

Answer 1

Answer:

2

Step-by-step explanation:

lim. sin8x/tan4x

x->0

dividing numerator and denominator by 8x so

lim

x->0 8xsin8x/8xtan4x we know sinx/x lim x->0 is 1 sio sin8x/8x=1

8x/tan4x lim->0

using l hôpital rule

differentiation of 8x->8

differentiation of tan4x->sec^2 4x. 4

thus the answer will be 8/sec^2 4x.4

substitution of x=0

8/4=2

thanks

Answer 2

Answer:

Step-by-step explanation: