lim sinx²/x²
x tends to 0
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1
Answer:
sin
²
x
x
lim
x
→
0
sin
x
x
⋅
sin
x
lim
x
→
0
sin
x
x
⋅
lim
x
→
0
sin
x
, we can seperate because sin x is continuous through the limit
=
1
⋅
0
=
0
because
lim
x
→
0
sin
x
x
=
1
is a very well known limit
OR
lim
x
→
0
sin
²
x
x
is
0
0
indeterminate, so we can use L'Hopital
=
lim
x
→
0
2
sin
x
cos
x
1
=
lim
x
→
0
sin
2
x
=
0
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