Math, asked by ansh2004y, 4 months ago

lim tan^2x-3/sec^2x-8
x--π/3

Answers

Answered by sainilavanya02

2

Answer:

lim_(x->pi/3)(tan^3x-3tanx)/(cos(x+pi/6))` `L'`Hospital rule `lim_(x->pi/3)(3tan^2x*sec^2x-2sec^2x)/(-sin(x+pi/6))` ...

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