Question

Lim tends to 0 4sinx-9xcosx/3x^2-5tan x

Answer 1

lim x->0 (4sinx-9xcosx)/3x^2-5tanx; apply L'hospital rule differentiate both numerator and denominator by x lim x->0 (4cosx -9(cosx-x sinx)) / 6x-5sec^2x ; lim x->0 (xsinx-5cosx) /6x-5sec^2 x and then put x=0 ,we will get answer as 1