Lim tends to 0 4sinx-9xcosx/3x^2-5tan x
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lim x->0 (4sinx-9xcosx)/3x^2-5tanx; apply L'hospital rule differentiate both numerator and denominator by x lim x->0 (4cosx -9(cosx-x sinx)) / 6x-5sec^2x ; lim x->0 (xsinx-5cosx) /6x-5sec^2 x and then put x=0 ,we will get answer as 1
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